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5x^2-264x+4=0
a = 5; b = -264; c = +4;
Δ = b2-4ac
Δ = -2642-4·5·4
Δ = 69616
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{69616}=\sqrt{16*4351}=\sqrt{16}*\sqrt{4351}=4\sqrt{4351}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-264)-4\sqrt{4351}}{2*5}=\frac{264-4\sqrt{4351}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-264)+4\sqrt{4351}}{2*5}=\frac{264+4\sqrt{4351}}{10} $
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